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What is round robin example?

Example of Round-robin Scheduling Step 1) The execution begins with process P1, which has burst time 4. Here, every process executes for 2 seconds. P2 and P3 are still in the waiting queue. Step 3) At time=4 , P2 is preempted and add at the end of the queue.

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What is Round-Robin Scheduling? The name of this algorithm comes from the round-robin principle, where each person gets an equal share of something in turns. It is the oldest, simplest scheduling algorithm, which is mostly used for multitasking. In Round-robin scheduling, each ready task runs turn by turn only in a cyclic queue for a limited time slice. This algorithm also offers starvation free execution of processes.

In this Operating system tutorial, you will learn:

Characteristics of Round-Robin Scheduling

Here are the important characteristics of Round-Robin Scheduling:

Round robin is a pre-emptive algorithm

The CPU is shifted to the next process after fixed interval time, which is called time quantum/time slice. The process that is preempted is added to the end of the queue.

Round robin is a hybrid model which is clock-driven

Time slice should be minimum, which is assigned for a specific task that needs to be processed. However, it may differ OS to OS. It is a real time algorithm which responds to the event within a specific time limit.

Round robin is one of the oldest, fairest, and easiest algorithm.

Widely used scheduling method in traditional OS.

Example of Round-robin Scheduling

Consider this following three processes

Process Queue Burst time P1 4 P2 3 P3 5

Step 1) The execution begins with process P1, which has burst time 4. Here, every process executes for 2 seconds. P2 and P3 are still in the waiting queue. Step 2) At time =2, P1 is added to the end of the Queue and P2 starts executing At time=4 , P2 is preempted and add at the end of the queue. P3 starts executing. Step 4) At time=6 , P3 is preempted and add at the end of the queue. P1 starts executing. Step 5) At time=8 , P1 has a burst time of 4. It has completed execution. P2 starts execution Step 6) P2 has a burst time of 3. It has already executed for 2 interval. At time=9, P2 completes execution. Then, P3 starts execution till it completes.

Step 7) Let’s calculate the average waiting time for above example.

Wait time P1= 0+ 4= 4 P2= 2+4= 6 P3= 4+3= 7

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Here, are pros/benefits of Round-robin scheduling method:

It doesn’t face the issues of starvation or convoy effect.

All the jobs get a fair allocation of CPU.

It deals with all process without any priority

If you know the total number of processes on the run queue, then you can also assume the worst-case response time for the same process. This scheduling method does not depend upon burst time. That’s why it is easily implementable on the system. Once a process is executed for a specific set of the period, the process is preempted, and another process executes for that given time period. Allows OS to use the Context switching method to save states of preempted processes.

It gives the best performance in terms of average response time.

Disadvantages of Round-robin Scheduling

Here, are drawbacks/cons of using Round-robin scheduling:

If slicing time of OS is low, the processor output will be reduced.

This method spends more time on context switching

Its performance heavily depends on time quantum.

Priorities cannot be set for the processes.

Round-robin scheduling doesn’t give special priority to more important tasks.

Decreases comprehension

Lower time quantum results in higher the context switching overhead in the system. Finding a correct time quantum is a quite difficult task in this system.

Worst Case Latency

This term is used for the maximum time taken for execution of all the tasks. dt = Denote detection time when a task is brought into the list

st = Denote switching time from one task to another

et = Denote task execution time

Formula:

T worst = {(dt i + st i + et i ), + (dt i + st i + et i ) 2 +...+ (dt i + st i + et i ) N ., + (dt i + st i + et i + et i ) N} + t ISR t, SR = sum of all execution times

Summary:

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