Wager Mage
Wager Mage
Photo: Erik Mclean
9:30–9:40 a.m. Stocks that open higher or lower than they closed typically continue rising or falling for the first five to 10 minutes… 9:40–10:00 a.m. … before reversing course for the next 20 minutes—unless the overnight news was especially significant.
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Read More »The surge in volume at the start of the day doesn't necessarily mean prices become more volatile. Buyers and sellers can balance each other out, creating a kind of equilibrium. But when news breaks outside of trading hours, an imbalance between buy and sell orders may cause a stock to open dramatically higher or lower than its price at the previous close. A stock hit by negative news often “gaps lower,” or opens much lower than it closed. In these cases, the stock tends to continue falling for the first five to 10 minutes as traders join the selling. This is typically followed by a recovery period for the next 20 minutes or so, as the overnight gap is “filled” as transactions go through and bargain-hunters step in (unless the news pushing the stock lower is truly disastrous). That initial fall can be alarming, especially if you're long the stock— meaning you bought it with the expectation that its price would rise—but don't overreact. It may be best to wait to see if it's going to keep falling or start rallying. One way to protect yourself against further declines is to set a stop order under the lowest price reached in the first 10 minutes. A stop order is an order to buy or sell a stock at the market price once the stock has traded at or through a specified price (the “stop price”). If the stock reaches the stop price, the order becomes a market order and is filled at the next available market price. Stocks that “gap up,” on the other hand, may present a great selling opportunity. Like downward trends at the open, upward trends tend to reverse themselves after the first five to 10 minutes, so you'll want to take advantage of the upside before the stock moves lower. In these situations, using a trailing stop that rises along with the stock may help maximize your selling price. In either case, you should know by 10 a.m. ET whether the opening trend will hold or reverse itself. One clue is the strength of the trend line. If the line is steep—think 45 degrees or greater—then the trend is likely to continue. But if it's relatively flat, there's a greater likelihood that the trend will fizzle out.
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Read More »144 The first 12 terms of the Fibonacci sequence are 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144. The 12th term (144) gives the number of rabbits after one year, which answers Fibonacci's original question to his readers.
It appears that your browser has JavaScript disabled. Rosalind requires your browser to be JavaScript enabled. The Fibonacci sequence is a sequence of numbers defined by the recurrence relation $F_n = F_{n-1} + F_{n-2}$ , where we set the starting values $F_1 = F_2 = 1$ . The Fibonacci sequence appears throughout the natural world, and it dates back over two millennia to its first use by Indian mathematicians; yet its name derives from Leonardo of Pisa, who popularized the sequence in the West by introducing it as an exercise involving a population of rabbits in 1202. His assumption about the population were as follows: The population begins in the first month with a pair of newborn rabbits. Rabbits reach reproductive age in one month. In any month, every rabbit of reproductive age mates with another rabbit of reproductive age. One month after two rabbits have mated, the female rabbit gives birth to a male and female rabbit. Rabbits never stop reproducing or die. See the figure below for a branching diagram illustrating the number of rabbit pairs for each of the first five months. The dynamics of the rabbit population explains the recurrence relation $F_n = F_{n-1} + F_{n-2}$ , as in the $n$ -th month, the total number of rabbits will equal the number of rabbits alive the previous month ( $F_{n-1}$ ) plus the number of newborn rabbits, which is equal to the number of adult rabbits, or the number of rabbits alive two months previously ( $F_{n-2}$ ). The first 12 terms of the Fibonacci sequence are 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144. The 12th term (144) gives the number of rabbits after one year, which answers Fibonacci's original question to his readers.
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